Q3 find the frequency of 1 to 9 from an array of size 100 having value 1 to 9 randomly arranged Conditions: 1. use only one loop. 2. do not use counters. 3. most efficiently Answer suppose if array of 100 with random values between 1 to 9 were given then simply answer is for(i=0;i<100;i++) { count[ arr[i] ]++; // arr[i] is given array and count[] is frequency counter. } complete program is like this #include<conio.h> #include<iostream.h> #include<stdlib.h> void main() { int arr[100],count[10],i,j; clrscr(); for(i=0;i<20;i++) { arr[i]=random(10); } for(i=0;i<20; i++) { cout<<arr[i]; if(i%10==0) ...